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210+8x-4.9x^2=0
a = -4.9; b = 8; c = +210;
Δ = b2-4ac
Δ = 82-4·(-4.9)·210
Δ = 4180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4180}=\sqrt{4*1045}=\sqrt{4}*\sqrt{1045}=2\sqrt{1045}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{1045}}{2*-4.9}=\frac{-8-2\sqrt{1045}}{-9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{1045}}{2*-4.9}=\frac{-8+2\sqrt{1045}}{-9.8} $
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